ada yang bisa bantu jawab? salah satunya jg gapapaa, thanks
[tex]\qty(2^{x})^2-8\cdot2^x+16=0\\\text{Lalu faktorkan}\\\qty(2^x-4)^2 = 0 \implies 2^x = 4 \implies x=2\\[/tex]
[answer.2.content]#Soysola (Spanish Edition)
[tex]\qty(2^{x})^2-8\cdot2^x+16=0\\\text{Lalu faktorkan}\\\qty(2^x-4)^2 = 0 \implies 2^x = 4 \implies x=2\\[/tex]
[answer.2.content]